1, 获取json字符串中属性（传统方式）

import net.sf.json.JSONObject JSONObject json = JSONObject.fromObject(response); json.getString("qrcode")

2，获取json字符串中属性（面向对象方式）

import com.fasterxml.jackson.databind.ObjectMapper PaymentResponse response = new ObjectMapper().readValue(json, PaymentResponse.class);

3，从json文件中反序列化

ObjectMapper mapper = new ObjectMapper();        InputStream is = WebServiceConfig.class.getResourceAsStream("/webservice.json");TypeFactory typeFactory = mapper.getTypeFactory();CollectionType collectionType = typeFactory.constructCollectionType(List.class, WebServiceConfig.class);        List
     
       config1 = mapper.readValue(is, collectionType);
     

如果不是集合对象则简单

ObjectMapper mapper = new ObjectMapper();        InputStream is = WebServiceConfig.class.getResourceAsStream("/webservice.json");WebServiceConfig config1 = mapper.readValue(is, WebServiceConfig.Class);

如果Json文件中有些属性是没有的要加上

mapper.configure(DeserializationFeature.FAIL_ON_UNKNOWN_PROPERTIES, false);

 4, 把对象转换成json字符串

JSONArray.fromObject(user)

 5，把json字符串转成对象

JSONObject jsonObject = JSONObject.fromObject(json);              BaseUserInfo Address  = (BaseUserInfo) JSONObject.toBean(jsonObject, BaseUserInfo.class);

 6,对象与json互转

ObjectMapper objectMapper = new ObjectMapper();  // 将Java对象序列化为Json字符串  String objectToJson = objectMapper.writeValueAsString(initUser());  System.out.println(objectToJson);  // 将Json字符串反序列化为Java对象  User user = objectMapper.readValue(objectToJson, User.class);  System.out.println(user);